$$\begin{gathered} \boxed{ A_l=P_b·h \\ A_t=A_l+2A_{b } \\ V=A_b·h} \\ {P}_b=3l \\ {A}_b=\frac{l^2\sqrt{3}}{4}. \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=P_b·h \\ A_t=A_l+2A_{b } \\ V=A_b·h} \\ {P}_b=3l \\ {A}_b=\frac{l^2\sqrt{3}}{4}. \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=P_b·h \\ A_t=A_l+2A_b \\ V=A_b·h \\ d=\sqrt{L^2+l^2+h^2} } \\ {P}_b=2L+2l \\ {A}_b=L·l \end{gathered}$$

sau:

$$\begin{gathered} \boxed{ A_l=h(2L+2l) \\ A_t=2(L·l+L·h+l·h) \\ V=L·l·h} \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=P_b·h \\ A_t=A_l+2A_b \\ V=A_b·h \\ d=\sqrt{L^2+l^2+h^2} } \\ {P}_b=2L+2l \\ {A}_b=L·l \end{gathered}$$

sau:

$$\begin{gathered} \boxed{ A_l=h(2L+2l) \\ A_t=2(L·l+L·h+l·h) \\ V=L·l·h} \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=4l^2 \\ A_t=6l^2 \\ V=l^3 \\ d=l\sqrt{3} } \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=4l^2 \\ A_t=6l^2 \\ V=l^3 \\ d=l\sqrt{3} } \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=\frac{P_b·a_p}{2} \\ A_t=A_l+A_b \\ V=\frac{A_b·h}{3}} \\ {P}_b=3l \\ {A}_b=\frac{l^2\sqrt{3}}{4} \end{gathered}$$

Alte formule utile:

$$\begin{gathered} AM=\frac{l\sqrt{3}}{2} \\ AO=\frac{2}{3}·AM=\frac{l\sqrt{3}}{3} \\ OM=\frac{1}{3}·AM=\frac{l\sqrt{3}}{6}. \end{gathered}$$

În particular, dacă VABC este tetraedru regulat (piramidă triunghiulară cu toate muchiile congruente), atunci putem aplica următoarele formule:

$$\begin{gathered} \boxed{ A_l=3·\frac{l^2\sqrt{3}}{4} \\ A_t=l^2\sqrt{3} \\ V=\frac{l^3\sqrt{2}}{12} \\ h=VO=\frac{l\sqrt{6}}{3} } \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=\frac{P_b·a_p}{2} \\ A_t=A_l+A_b \\ V=\frac{A_b·h}{3}} \\ {P}_b=3l \\ {A}_b=\frac{l^2\sqrt{3}}{4} \end{gathered}$$

Alte formule utile:

$$\begin{gathered} AM=\frac{l\sqrt{3}}{2} \\ AO=\frac{2}{3}·AM=\frac{l\sqrt{3}}{3} \\ OM=\frac{1}{3}·AM=\frac{l\sqrt{3}}{6}. \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=\frac{P_b·a_p}{2} \\ A_t=A_l+A_{b } \\ V=\frac{A_b·h}{3}} \\ {P}_b=4l \\ {A}_b=l^2. \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=\frac{P_b·a_p}{2} \\ A_t=A_l+A_{b } \\ V=\frac{A_b·h}{3}} \\ {P}_b=4l \\ {A}_b=l^2. \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=\frac{P_b·a_p}{2} \\ A_t=A_l+A_{b } \\ V=\frac{A_b·h}{3}} \\ {P}_b=6l \\ {A}_b=6·A_{△BOC}=6·\frac{l^2\sqrt{3}}{4} \\ {A}_b=\frac{3l^2\sqrt{3}}{2} \end{gathered}$$

Alte formule utile:

$$\begin{gathered} OC=OD=CD=l \\ OM=\frac{l\sqrt{3}}{2}. \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=\frac{P_b·a_p}{2} \\ A_t=A_l+A_{b } \\ V=\frac{A_b·h}{3}} \\ {P}_b=6l \\ {A}_b=6·A_{△BOC}=6·\frac{l^2\sqrt{3}}{4} \\ {A}_b=\frac{3l^2\sqrt{3}}{2} \end{gathered}$$

Alte formule utile:

$$\begin{gathered} OC=OD=CD=l \\ OM=\frac{l\sqrt{3}}{2}. \end{gathered}$$

Notații:

$$\begin{gathered} B=baza mare \left(ABCD\right) \\ b=baza mică (A`B`C`D`) \\ L=AB (latura bazei mari) \\ l=A`B` (latura bazei mici) \\ {P}_B=perimetrul bazei mari \\ {P}_b=perimetrul bazei mici \\ {A}_B=aria bazei mari \\ {A}_b=aria bazei mici \\ h=O`O (înălțimea trunchiului) \\ {a}_t=M`M (apotema trunchiului) \end{gathered}$$

Formulele de mai jos sunt valabile pentru orice trunchi de piramidă regulată:

$$\begin{gathered} \boxed{ A_l=\frac{(P_B+P_b)·a_t}{2} \\ A_t=A_l+A_B+A_b \\ V=\frac{h}{3}(A_B+A_b+\sqrt{A_B·A_b}) } \end{gathered}$$

Dacă avem trunchi de piramidă patrulateră regulată, atunci:

$$\begin{gathered} P_B=4L \\ {P}_b=4l \\ {A}_B=L^2 \\ {A}_b=l^2 \end{gathered}$$

Dacă avem trunchi de piramidă triunghiulară regulată, atunci:

$$\begin{gathered} P_B=3L \\ {P}_b=3l \\ {A}_B=\frac{L^2\sqrt{3}}{4} \\ {A}_b=\frac{l^2\sqrt{3}}{4}. \end{gathered}$$

Notații:

$$\begin{gathered} B=baza mare \\ b=baza mică \\ L=latura bazei mari \\ l=latura bazei mici \\ {P}_B=perimetrul bazei mari \\ {P}_b=perimetrul bazei mici \\ {A}_B=aria bazei mari \\ {A}_b=aria bazei mici \\ h=înălțimea trunchiului \\ {a}_t=apotema trunchiului \end{gathered}$$

$$\begin{gathered} \boxed{ A_l=\frac{(P_B+P_b)·a_t}{2} \\ A_t=A_l+A_B+A_b \\ V=\frac{h}{3}(A_B+A_b+\sqrt{A_B·A_b}) } \end{gathered}$$

Dacă avem trunchi de piramidă triunghiulară regulată, atunci:

$$\begin{gathered} P_B=3L \\ {P}_b=3l \\ {A}_B=\frac{L^2\sqrt{3}}{4} \\ {A}_b=\frac{l^2\sqrt{3}}{4}. \end{gathered}$$